Tentukan hasil operasi bilangan berpangkat berikut ini.
[tex] {3}^{1} + {3}^{0} = [/tex]
[tex]( - 2)^{ - 6} = [/tex]
[tex]( { - 3}^{3}) \times ( { - 3}^{0} ) = [/tex]
[tex]( \frac{1}{6} )^{ - 3} = [/tex]
[tex]( - \frac{2}{3})^{ - 2} [/tex]
#No ngasal
#No copas
#Boleh kalkulator
# Semoga Berhasil #
Jawaban:
penjelasan dengan langkah langkah
Penyelesaian :
[tex]1. \: \: {3}^{1} + {3}^{0} \\ =3 + 1 \\ \boxed{ \blue{ =4 }} \\ \\ \\ \\ 2. \: \: ( - 2) ^{ - 6} \\ = \frac{1}{ {( - 2)}^{6} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{( - 2) \times ( - 2) \times ( - 2) \times ( - 2) \times ( -2 ) \times ( - 2)} \\ \\ \boxed{ \green{= 64}} \\ \\ \\ \\ 3. \: \: ( - 3) \times ( { - 3}^{0} ) \\ = - 27 \times - 1 \\ = 27 \times 1 \\ \boxed{ \red{=27 }} \\ \\ \\ \\ 4. \: \: ( \frac{1}{6})^{ - 3} \\ \\ = \frac{1}{ (\frac{1}{6}) ^{ - 3} } \\ \\ \boxed{ \purple{=216 }} \\ \\ \\ \\ 5. \: \: ( - \frac{2}{3})^{ - 2} \\ \\ = \frac{1}{ { - \frac{2}{3} }^{2} } \\ \\ \boxed{ \blue{ = \frac{9}{4} }}[/tex]
